Questions
A particle executing harmonic motion is having velocities v1 and v2 at distances is x1 and x2 from the equilibrium position. The amplitude of the motion is
detailed solution
Correct option is C
v1=ωa2−x12, v2=ωa2−x22 We get, a=v12x22−v22x12v12−v22Talk to our academic expert!
Similar Questions
A horizontal platform with an object placed on it is executing S.H.M. in the vertical direction. The amplitude of oscillation is . What must be the least period of these oscillations, so that the object is not detached from the platform
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