Download the app

Questions  

A particle executing harmonic motion is having velocities v1 and v2 at distances is x1 and x2 from the equilibrium posi­tion. The amplitude of the motion is

a
v12x2−v22x1v12+v22
b
v12x12−v22x22v12+v22
c
v12x22−v22x12v12+v22
d
v12x22+v22x12v12+v22

detailed solution

Correct option is C

v1=ωa2−x12, v2=ωa2−x22. We get a=v12x22−v22x12v12−v22.

Talk to our academic expert!

+91

Are you a Sri Chaitanya student?


Similar Questions

One end of an ideal spring is connected with a smooth block with the other end with rear wall of driving cabin of a truck as shown in figure. Initially, the system is at rest. If truck starts to accelerate with a constant acceleration ‘a’ , then the block (relative to truck ):


phone icon
whats app icon