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A particle executing harmonic motion is having velocities v1 and v2 at distances is x1 and x2 from the equilibrium posi­tion. The amplitude of the motion is

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a

v12x2−v22x1v12+v22

b

v12x12−v22x22v12+v22

c

v12x22−v22x12v12+v22

d

v12x22+v22x12v12+v22

answer is C.

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Detailed Solution

v1=ωa2−x12, v2=ωa2−x22. We get a=v12x22−v22x12v12−v22.
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A particle executing harmonic motion is having velocities v1 and v2 at distances is x1 and x2 from the equilibrium posi­tion. The amplitude of the motion is