Download the app

Questions  

A particle is executing linear SHM. The average kinetic energy and average potential energy, over a period of oscillation, respectively are Kav and Uav. Then,

a
Kav = Uav2
b
Uav = Kav2
c
Kav = Uav
d
Uav = Kav3

detailed solution

Correct option is C

K = 12mv2 = 12mA2ω2cos2ωtAverage value of cos2 ωt is 12 over one cycle∴  Kav = 14mω2A2------------(i)      U = 12mω2x2 = 12mω2A2sin2ωtAverage value of sin2 ωt is 12 over one cycle.∴  Uav = 14mω2A2 ---------(iii)From Eqs. (i) and (ii), we get Kav = Uav

Talk to our academic expert!

+91

Are you a Sri Chaitanya student?


Similar Questions

The identical springs of constant ‘K’ are connected in series and parallel as shown in figure A mass M is suspended from them. The ratio of their frequencies of vertical oscillations will be


phone icon
whats app icon