A particle is executing a motion in which its displacement as a function of time is given by x = 3 sin(5πt+π3)+cos(5πt+π3) where x is in m and t is in s. Then the motion is
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a
simple harmonic with time period 0.2 s
b
simple harmonic with time period 0.4 s
c
simple harmonic with amplitude 3 m
d
not a simple harmonic but a periodic motion
answer is B.
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Detailed Solution
x = 3 sin(5πt+π3)+cos(5πt+π3)Amplitude = xmax = 32+12 = 10, ω = 5πT = 2πω = 2π5π = 0.4 s
A particle is executing a motion in which its displacement as a function of time is given by x = 3 sin(5πt+π3)+cos(5πt+π3) where x is in m and t is in s. Then the motion is