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A particle is executing a motion in which its displacement as a function of time is given by $x = 3 \sin (5 π t + π / 3) + \cos (5 π t + π / 3)$ where x is in m and t is in s. Then the motion is

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simple harmonic with time period 0.2 s

simple harmonic with time period 0.4 s

simple harmonic with amplitude 3 m

not a simple harmonic but a periodic motion

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detailed solution

Correct option is B

x=3sin⁡(5πt+π/3)+cos⁡(5πt+π/3) Amplitude =xmax=32+12=10,ω=5πT=2πω=2π5π=0.4s

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A particle is executing a motion in which its displacement as a function of time is given by x=3sin⁡(5πt+π/3)+cos⁡(5πt+π/3) where x is in m and t is in s. Then the motion is

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Ready to Test Your Skills?

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A particle is executing a motion in which its displacement as a function of time is given by $x = 3 \sin (5 π t + π / 3) + \cos (5 π t + π / 3)$ where x is in m and t is in s. Then the motion is