A particle is executing SHM according to the equation x=Acosωt. Average speed of the particle during the interval 0≤t≤π6ω.
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a
3Aω2
b
3Aω4
c
3Aωπ
d
3Aωπ(2−3)
answer is D.
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Detailed Solution
Average velocity v¯=∫0t dxdt⋅dtt=∫0t dxt=x(t)−x(0)t=A(cosπ/6−1)π/6ω=3Aωπ(3−2)Since particle does not change its direction in the given interval, average speed becomes |v¯|=3Aωπ(2−3)