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A particle executing S.H.M. of amplitude 4 cm and T = 4 sec. The time taken by it to move from positive extreme position to half the amplitude is

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detailed solution

Correct option is C

Equation of motion y=acosωt⇒a2=acosωt⇒cosωt=12⇒ωt=π3⇒2πtT=π3⇒t=π3×T2π=43×2=23sec

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