Questions
A particle executing SHM of amplitude 4 cm and T = 4 sec. The time taken by it to move from positive extreme position to half the amplitude is
detailed solution
Correct option is C
Equation of motion y=acosωt⇒ a2=acosωt⇒cosωt=12⇒ωt=π3⇒ 2πtT=π3⇒t=π3×T2π=43×2=23secTalk to our academic expert!
Similar Questions
A horizontal platform with an object placed on it is executing S.H.M. in the vertical direction. The amplitude of oscillation is . What must be the least period of these oscillations, so that the object is not detached from the platform
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