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Questions  

A particle executing SHM of amplitude ‘a’ has a displacement  a2 at t = T4 and a negative velocity. The epoch  or initial phase of the particle is  

 

a
π3
b
2π3
c
5π3
d
π

detailed solution

Correct option is A

assuming the displacement equation is x= asinωt+ϕ =a2sinωt+ϕ =12 (here ωt=ωT4=π2)  sin90 +ϕ=sin1500  ( as velocity is negative phase must be more than 900)ϕ =600

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