Questions
A particle executing SHM of amplitude 'a' has a displacement a/2 at t = T/4 and a negative velocity. The epoch of the particle is
detailed solution
Correct option is A
Equation of SHM =ysin(ωt+ϕ) When y=a2,t=T4=2π4ω=π2ωv=aωcos(ωt+ϕ) velocity is negativeπ2<(ωt+ϕ)<3π2a2=asin(ωt+ϕ) ⇒sin(ωt+ϕ)=12π2+ϕ=5π6 Substituting in the above equation, we get ϕ=π/3Talk to our academic expert!
Similar Questions
A horizontal platform with an object placed on it is executing S.H.M. in the vertical direction. The amplitude of oscillation is . What must be the least period of these oscillations, so that the object is not detached from the platform
799 666 8865
support@infinitylearn.com
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
free study material
JEE Mock Tests
JEE study guide
JEE Revision Notes
JEE Important Questions
JEE Sample Papers
JEE Previous Year's Papers
NEET previous year’s papers
NEET important questions
NEET sample papers
NEET revision notes
NEET study guide
NEET mock tests
