Questions
A particle is executing SHM of amplitude A and time period T along a straight line. Then time required for the particle to directly move from
detailed solution
Correct option is D
∠POM=cos−1OMOP = cos−1 A/2A = π4 ∠QON=cos−1ONOQ = cos−1 A/2A = π3 ∴ ∠POQ= π4+π3=7π12 π−π4+π3=π−7π12=5π12 ∴ t=5π/12ω=5π/122π/T= 5T24Talk to our academic expert!
Similar Questions
A particle is oscillating along a straight line with time period 6 sec and amplitude ‘A’. Then the time taken by the particle to directly move from to is
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