For the particle executing SHM of the displacement x is given by x = A cos ωt. Identify which represents variation of potential energy as a function of time t and displacement x.
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a
I, III
b
II, IV
c
II, III
d
I, IV
answer is A.
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Detailed Solution
PE=12mω2x2=12mω2A2cos2ωtThat is at t = 0 potential energy is maximum and potential energy a x2. So choice is I and II.