First slide
Simple harmonic motion
Question

For the particle executing SHM of the displacement x is given by x = A cos ωt.  Identify which represents variation of potential energy as a function of time t and  displacement x.

Easy
Solution

PE=12mω2x2=12mω2A2cos2ωt

That is at t = 0 potential energy is maximum and potential energy a x2. So choice is  I and II.

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