A particle executing SHM has a time period of 12 s and after two seconds from start, when it passes through the mean position its velocity is found to be 3.142cms−1. Find the amplitude of oscillations.
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a
6 cm
b
3 cm
c
24 cm
d
12 cm
answer is A.
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Detailed Solution
Velocity at mean position = Aω = π ⇒A.2πT=π ⇒A=122 cm = 6 cm