A particle executing SHM having amplitude 5cm, mass 0.5 kg and angular frequency 5 rad/s is at 1cm from mean position. Find potential energy and kinetic energy.

Given, m=0.5 kg, ω=5 rad/s,               x=1 cm = 10-2m,               A=5 cm=5×10-2m∴ Potential energy PE=12mω2x2or        PE=12×0.5×(5)2×10-22                 =254×10-4 J=6.25×10-4 J∴ Kinetic energy, KE=12mω2(A2-x2)or        KE=12×0.5×(5)2(25-1)×10-4                =150×10-4 J