First slide

Simple harmonic motion

Question

A particle is executing S.H.M. If its amplitude is 2 m and periodic time 2 seconds, then the maximum velocity of the particle will be

Easy

A

$π m / s$
B

$\sqrt{2 π} m / s$
C

$2 π m / s$
D

$4 π m / s$

Solution

$v_{\max} = ωa = \frac{2 π}{T} \times a$ $\Rightarrow v_{\max} = \frac{2 \times π \times 2}{2} = 2 π m / s$

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