Questions
A particle is executing SHM in a straight line. Let x, v, and a represent instantaneous displacement, velocity and acceleration respectively. Graph of a2 vs v2 is
detailed solution
Correct option is C
Displacement, x=Asinωt+ϕVelocity, v=Aωcosωt+ϕAcceleration, a=−Aω2sinωt+ϕ v=ωA2−x2⇒v2=ω2A2−x2 ...(1) a=−ω2x⇒a2=ω2x2 ...(2)(2) in (1) gives,So, v2=ω2A2−a2ω4⇒v2A2ω2+a2A2ω4=1 It is of the form yK1+xK2=1 , where K1 and K2 are positive constants. y=1K1−xK2K1⇒y=c−mx. It is a straight line with negative slope and positive intercept.Talk to our academic expert!
Similar Questions
The acceleration a of a particle undergoing S.H.M. is shown in the figure. Which of the labelled points corresponds to the particle being at – xmax
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