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Q.

A particle is executing simple harmonic motion according to the equation x=(5cos⁡100t+12sin⁡100t) cm where t is time in second. Then maximum velocity of the particle is

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a

12 m/s

b

13 m/s

c

17 m/s

d

8 m/s

answer is B.

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Detailed Solution

x=(5cos⁡100t+12sin⁡100t)cmAmplitude=52+122⇒A=13 cm; Angular frequency ω=100 rad/s∴ Vmax⁡=ωA=100×(13×10−2)m/s=13 m/s
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A particle is executing simple harmonic motion according to the equation x=(5cos⁡100t+12sin⁡100t) cm where t is time in second. Then maximum velocity of the particle is