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A particle is executing simple harmonic motion according to the equation cm where t is time in second. Then maximum velocity of the particle is
detailed solution
Correct option is B
x=(5cos100t+12sin100t)cmAmplitude=52+122⇒A=13 cm; Angular frequency ω=100 rad/s∴ Vmax=ωA=100×(13×10−2)m/s=13 m/sTalk to our academic expert!
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The identical springs of constant ‘K’ are connected in series and parallel as shown in figure A mass M is suspended from them. The ratio of their frequencies of vertical oscillations will be
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