A particle is executing simple harmonic motion along a straight line with amplitude 2 cm. Maximum restoring force acting on the particle is 2N. Find the distance of the particle from the equilibrium position when restoring force acting on the particle is 1N.

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0.25 cm

0.5 cm

1 cm

0.75 cm

answer is C.

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Detailed Solution

Restoring force F=mω2x=m.ω2A.xA=FmxA⇒x=FFmA=122cm=1 cm

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