Questions
A particle is executing simple harmonic motion along a straight line with amplitude 2 cm. When the particle is at a distance of 1 cm from its equilibrium position, its velocity is equal to . Then time period of oscillation is
detailed solution
Correct option is D
V=ωA2−x2⇒V=ωA1−x2A2⇒V=Vm1−x2A2when x=A2, V=4Cms∴ T=2πω=2π4/3sec=3.π2secTalk to our academic expert!
Similar Questions
One end of an ideal spring is connected with a smooth block with the other end with rear wall of driving cabin of a truck as shown in figure. Initially, the system is at rest. If truck starts to accelerate with a constant acceleration ‘a’ , then the block (relative to truck ):
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