Questions
A particle is executing simple harmonic motion along a straight line with time period T and amplitude A. Find the speed of the particle when its kinetic energy is equal to its potential energy.
detailed solution
Correct option is D
Speed v=ωA2-x2, KE=12mv2 and PE=12mω2x2∴12mω2(A2-x2)=12mω2x2⇒x=A2∴v=ωA2-A22=2πATTalk to our academic expert!
Similar Questions
One end of an ideal spring is connected with a smooth block with the other end with rear wall of driving cabin of a truck as shown in figure. Initially, the system is at rest. If truck starts to accelerate with a constant acceleration ‘a’ , then the block (relative to truck ):
799 666 8865
support@infinitylearn.com
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
free study material
JEE Mock Tests
JEE study guide
JEE Revision Notes
JEE Important Questions
JEE Sample Papers
JEE Previous Year's Papers
NEET previous year’s papers
NEET important questions
NEET sample papers
NEET revision notes
NEET study guide
NEET mock tests
