Download the app

Simple hormonic motion

Question

A particle  is executing simple harmonic motion along a straight line. When its distance from the equilibrium position is 3cm its velocity is 20cm/s. When the particle is at a distance of 4 cm from the equilibrium position, its velocity is 15cm/s . Then amplitude of oscillation is 

Moderate
Solution

Using v=ωA2-x2,

We can write 20=ωA2-32, andm 15=ωA2-42,

A2-42A2-32=152016(A2-16)=9(A2-9)A=5cm



Talk to our academic expert!

+91

Are you a Sri Chaitanya student?



Similar Questions

One end of an ideal spring is connected with a smooth block with the other end with rear wall of driving cabin of a truck as shown in figure. Initially, the system is at rest. If truck starts to accelerate with a constant acceleration ‘a’ , then the block (relative to truck ):


phone icon
whats app icon