First slide

Simple harmonic motion

Question

A particle executing simple harmonic motion of amplitude 5 cm has maximum speed of 31.4 cm/s. The frequency of its oscillation is

Moderate

A

3 Hz
B

2 Hz
C

4 Hz
D

1 Hz

Solution

$v_{\max} = aω = a \times 2 πn$ $\Rightarrow n = \frac{v_{\max}}{2 πa} = \frac{31 .4}{2 \times 3 .14 \times 5} = 1 Hz$

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