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Q.

A particle executing simple harmonic motion of amplitude 5 cm has maximum speed of 31.4 cm/s. The frequency of its oscillation is

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a

3 Hz

b

2 Hz

c

4 Hz

d

1 Hz

answer is D.

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Detailed Solution

vmax=aω=a×2πn ⇒n=vmax2πa=31.42×3.14×5=1 Hz
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