Questions
A particle executing simple harmonic motion of amplitude 5 cm has maximum speed of 31.4 cm/s. The frequency of its oscillation is
detailed solution
Correct option is A
Maximum speed of a particle executing SHM isumax = aω = a(2πn)⇒n = umax2πaHere, umax = 31.4 cm/s, a = 5 cmSubstituting, the given values, we haven = 31.42×3.14×5 =1 HzTalk to our academic expert!
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The identical springs of constant ‘K’ are connected in series and parallel as shown in figure A mass M is suspended from them. The ratio of their frequencies of vertical oscillations will be
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