First slide

Simple hormonic motion

Question

A particle executing simple harmonic motion of amplitude 5 cm has maximum speed of 31.4 cm/s. The frequency of its oscillation is

Easy

A

1 Hz
B

3 Hz
C

2 Hz
D

4 Hz

Solution

$v_{\max} = Aω \Rightarrow f = \frac{ω}{2 π} = \frac{v_{\max}}{2 πa} = \frac{31.4}{2 π \times 5} = 1 Hz$

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