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Questions  

A particle executing simple harmonic motion of amplitude 5 cm has maximum speed of 31.4 cm/s. The frequency of its oscillation is

a
1 Hz
b
3 Hz
c
2 Hz
d
4 Hz

detailed solution

Correct option is A

vmax=Aω⇒f=ω2π=vmax2πa=31.42π×5=1 Hz

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