Questions
A particle is executing simple harmonic motion. The equation of motion is given by . Then their time period of oscillation is (in seconds)
detailed solution
Correct option is D
A simple harmonic motion can be represented by the equation a=−ω2x . where acceleration a can be written as d2xdt2 . Hence d2xdt2=−ω2x . Writing the given equation d2xdt2+4x=0 in the above form, we get d2xdt2=−4x. Comparing this with the above equation, we get ω2=4. Taking square root on both sides ω=2Using the relation ω=2πT, we get 2=2πTHence, time period of oscillation is π sSimilar Questions
A particle executes simple harmonic motion (amplitude = A) between and . The time taken for it to go from 0 to A/2 is and to go from A/2 to A is . Then
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