Questions
A particle is executing simple harmonic motion. The equation of motion is given by . Then their time period of oscillation is (in seconds)
detailed solution
Correct option is D
A simple harmonic motion can be represented by the equation a=−ω2x . where acceleration a can be written as d2xdt2 . Hence d2xdt2=−ω2x. Writing the given equation d2xdt2+4x=0 in the above form, we get d2xdt2=−4x . Comparing this with the above equation, we get ω2=4. Taking square root on both sides ω=2Using the relation ω=2πT, we get substitute ω=22=2πT ⇒T=π second=time period of oscillationTalk to our academic expert!
Similar Questions
A body executes S.H.M. under the action of a force F1 with a time period 7/6 seconds. If the force is changed to F2 it executes S.H.M. with time period 7/8 seconds. If both the forces F1 and F2 act simultaneously in the same direction on the body, then its time period in seconds is
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