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Q.

A particle executing simple harmonic motion is given by y=8sinπ10t−12 where y  is in metre, and t is in seconds. Then the average speed of the particle during one  full oscillation is

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a

80 m/s

b

0.8 m/s

c

40 m/s

d

160 m/s

answer is D.

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Detailed Solution

Average speed of a particle executing simple harmonic motion can be written as Total   DistanceTotal   time   In a simple harmonic motion, the total distance travelled by the particle is 4 times  the amplitude. The total time taken is one full time period of oscillation.Therefore, Average    speed=Total   DistanceTotal   time=4AT Comparing the given equation y=8sinπ10t−12 with standard equation,  y=Asinωt+ϕ , we get  A=8  m and   ω=10π.Using the relation  ω=2πT, we get  10π=2πT i.e. T=15  s.Hence  Average    speed=4AT=4×815=160  m/s.
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