Questions
A particle executing simple harmonic motion has an amplitude of 6 cm. Its acceleration at a distance of 2 cm from the mean position is . The maximum speed of the particle is
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Correct option is B
A=ω2y ⇒ω=A/y=82=2 rad/secNow vmax=aω=6×2=12 cm/secSimilar Questions
A horizontal platform with an object placed on it is executing S.H.M. in the vertical direction. The amplitude of oscillation is . What must be the least period of these oscillations, so that the object is not detached from the platform
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