Questions
A particle is executing a simple harmonic motion. Its maximum acceleration is and maximum velocity is . Then, its time period of vibration will be:
detailed solution
Correct option is A
Maximum velocity Vmax = Aω = β-------(i)maximum acceleration αmax = Aω2 = α-------(ii)Equation (ii) divided by (i) ω = ωβ ⇒ 2πT = ωβT = 2πβαTalk to our academic expert!
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The identical springs of constant ‘K’ are connected in series and parallel as shown in figure A mass M is suspended from them. The ratio of their frequencies of vertical oscillations will be
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