Questions  

A particle is executing a simple harmonic motion. Its maximum acceleration is α and maximum velocity is β. Then, its time period of vibration will be

Unlock the full solution & master the concept.

Get a detailed solution and exclusive access to our masterclass to ensure you never miss a concept
By Expert Faculty of Sri Chaitanya
ctaimg
a
β2α
b
2πβα
c
β2α2
d
αβ
NEW

Ready to Test Your Skills?

Check Your Performance Today with our Free Mock Tests used by Toppers!

detailed solution

Correct option is B

If  A  and ω  be amplitude and angular frequency of  vibration, thenα=ω2A                    . . . . (i) and β=ωA          . . . . .(ii)Diving eqn. (i) by eqn. (ii), we getαβ=ω2AωA=ω∴   Time period of vibration is T=2πω=2π(α/β)=2πβα


ctaimg

Similar Questions

One end of an ideal spring is connected with a smooth block with the other end with rear wall of driving cabin of a truck as shown in figure. Initially, the system is at rest. If truck starts to accelerate with a constant acceleration ‘a’ , then the block (relative to truck ):

Want to Improve your productivity
talk to our academic experts now !!

counselling
india
+91

whats app icon