Questions
A particle is executing a simple harmonic motion. Its maximum acceleration is and maximum velocity is . Then, its time period of vibration will be
detailed solution
Correct option is B
If A and ω be amplitude and angular frequency of vibration, thenα=ω2A . . . . (i) and β=ωA . . . . .(ii)Diving eqn. (i) by eqn. (ii), we getαβ=ω2AωA=ω∴ Time period of vibration is T=2πω=2π(α/β)=2πβαTalk to our academic expert!
Similar Questions
One end of an ideal spring is connected with a smooth block with the other end with rear wall of driving cabin of a truck as shown in figure. Initially, the system is at rest. If truck starts to accelerate with a constant acceleration ‘a’ , then the block (relative to truck ):
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