First slide
Simple hormonic motion
Question

A particle is executing a simple harmonic motion. Its maximum acceleration is α and maximum velocity is β. Then, its time period of vibration will be

Easy
Solution

If  A  and ω  be amplitude and angular frequency of  vibration, then

α=ω2A                    . . . . (i)

 and β=ωA          . . . . .(ii)

Diving eqn. (i) by eqn. (ii), we get

αβ=ω2AωA=ω

   Time period of vibration is 

T=2πω=2π(α/β)=2πβα

 

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