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Questions  

 For a particle executing simple harmonic motion, the kinetic energy K is given by K=K0cos2ωt The maximum value of potential energy is

a
K0
b
zero
c
K0/2
d
not obtainable

detailed solution

Correct option is A

K=K0cos2⁡ωt Kmax=K0  (P.E.) max=Kmax=K0

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