Questions
For a particle executing simple harmonic motion, the kinetic energy K is given by . The maximum value of potential energy is
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a
K0
b
Zero
c
K02
d
Not obtainable
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Correct option is A
Since maximum value of cos2ωt is 1. ∴Kmax=Kocos2ωt=KoAlso Kmax=PEmax=Ko(Assuming minimum PE = 0)Similar Questions
When the displacement is half the amplitude, the ratio of potential energy to the total energy is
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