First slide
Simple harmonic motion
Question

For a particle executing simple harmonic motion, the kinetic energy K is given by K=Kocos2ωt . The maximum value of potential energy is

Moderate
Solution

Since maximum value of cos2ωt is 1.
 Kmax=Kocos2ωt=Ko
Also  Kmax=PEmax=Ko

(Assuming minimum PE = 0)

Get Instant Solutions
When in doubt download our app. Now available Google Play Store- Doubts App
Download Now
Doubts App