First slide

Simple harmonic motion

Question

For a particle executing simple harmonic motion, the kinetic energy K is given by, $K_{0} \cos^{2} ω t$ .The maximum value of PE is

Easy

A

$K_{0}$
B

$2 K_{0}$
C

$3 K_{0}$
D

$4 K_{0}$

Solution

The mechanical energy of a simple harmonic motion is conserved. Since $K = K_{0}$ $\cos^{2} ω t$ , the maximum value of Kinetic energy = $K_{0}$ = maximum value of potential energy at the extreme position of the body in simple harmonic motion.

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