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Q.

For a particle executing simple harmonic motion,  the kinetic energy K is given by, K0cos2⁡ωt.The maximum value of PE is

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a

K0

b

2K0

c

3K0

d

4K0

answer is A.

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Detailed Solution

The mechanical energy of a simple harmonic motion is conserved. Since K=K0  cos2⁡ωt, the maximum value of Kinetic energy = K0 = maximum value of potential  energy at the extreme position of the body in simple harmonic motion.
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