Questions
A particle is executing simple harmonic motion with frequency f. The frequency at which its kinetic energy change into potential energy is
a
f/2
b
f
c
2 f
d
4 f
detailed solution
Correct option is C
KE=12mv2=12mωAcosωt2 =12mω2A2cos2ωt =12mω2A21+cos2ωt2 =14mω2A2+14mω2A2cos2ωtIn S.H.M., frequency of K.E. and P.E. = 2 × (Frequency of oscillating particle)Talk to our academic expert!
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When the displacement is half the amplitude, the ratio of potential energy to the total energy is
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