A particle experiences constant acceleration for 20 seconds after starting from rest. If it travels a distance s1, in the first 10 second and distance s2 in the next 10 seconds, then

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s2 = s1

s2 = 2s1

s2 = 3s1

s2 = 4s1

answer is C.

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Detailed Solution

Let a be the constant acceleration of the particle. Thens=ut+12at2or s1=0+12×a×(10)2=50a∴s1+s2s1=200a50a=4Or s1+s2=4s1 or s2=4s1−s1=3s1