First slide
Instantaneous acceleration
Question

A particle experiences constant acceleration for 20 seconds after starting from rest. If it travels a distance s1, in the first 10 second and distance s2 in the next 10 seconds, then

Easy
Solution

Let a be the constant acceleration of the particle. Then
s=ut+12at2
or s1=0+12×a×(10)2=50a
s1+s2s1=200a50a=4
Or s1+s2=4s1 or s2=4s1s1=3s1

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