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Q.

A particle is fired with speed u making angle θ with the horizontal. Its potential energy at the highest point is

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a

12mu2sin2⁡θ

b

12mu2cos2⁡θ

c

12mu2

d

12mu2sin2⁡2θ

answer is A.

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Detailed Solution

The vertical component of velocity is reduced to zero. The corresponding kinetic energy is converted into potential energy P.E. =mgH = mgu2sin2θ2g=12mu2sin2θ
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A particle is fired with speed u making angle θ with the horizontal. Its potential energy at the highest point is