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Questions  

A particle is fired with speed u making angle θ with the horizontal. Its potential energy at the highest point is

a
12mu2sin2⁡θ
b
12mu2cos2⁡θ
c
12mu2
d
12mu2sin2⁡2θ

detailed solution

Correct option is A

The vertical component of velocity is reduced to zero. The corresponding kinetic energy is converted into potential energy P.E. =mgH = mgu2sin2θ2g=12mu2sin2θ

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