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Questions  

A particle A has charge +q and a particle B has charge +4q with each of them having the same mass m. When al.lowed to fall from rest through the same electric potential difference, the ratio of their speed vAvB will become

a
2 : 1
b
1 : 2
c
1 : 4
d
4 : 1

detailed solution

Correct option is B

Using v=2QVm ⇒v∝Q⇒vAvB=QAQB=q4q=12

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