Questions
A particle A has charge +q and particle I has charge + 4 q with each of them having the same mass m. When allowed to faII from rest through the same electric potential difference, the ratio of their speeds VA/VB will become
detailed solution
Correct option is B
Acceleration = (Force/mass)∴a=Fm=qEmSo, aA=4aB Now, v2=u2+2ax, where u=0and x is same for both particle∴ VA2=2aAx and VB2=2aBxor VA2VB2=aAaB=14or VAVB=12 or VA:VB=1:2Talk to our academic expert!
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