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A particle has initial velocity ( $2 \hat{i} + 3 \hat{j}$ ) and acceleration ( $0.3 \hat{i} + 0.2 \hat{j}$ ). The magnitude of velocity after 10 seconds will be

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detailed solution

Correct option is C

v→ = u→+a→t = (2i^+3j^)+(0.3i^+0.2j^)×10 = (5i^+5j^) ⇒ v→ =52

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A particle has initial velocity (2i^+3j^) and acceleration (0.3i^+0.2j^). The magnitude of velocity after 10 seconds will be

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A particle has initial velocity ( $2 \hat{i} + 3 \hat{j}$ ) and acceleration ( $0.3 \hat{i} + 0.2 \hat{j}$ ). The magnitude of velocity after 10 seconds will be