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A particle has initial velocity (2i^+3j^) and acceleration (0.3i^+0.2j^). The magnitude of velocity after 10 seconds will be

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a
9 units
b
92   units
c
52  units
d
5 units

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detailed solution

Correct option is C

v→ = u→ +at→= (2i^+3j^) +(0.3i^+0.2j^)×10= 5i^+5j^      ⇒  |v|→= 52 units


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