A particle has a mass 400 times greater than that of the electron and charge is double than that of a electron. It is accelerated by 5 V of potential difference. Initially the particle was at rest, then its final kinetic energy will be___eV.

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Detailed Solution

Gain in K.E is equal to loss in P.EK.E = P.E = qV = (2e) (5 V) = 10eV

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