First slide

Electrostatic potential energy

Question

A particle has a mass 400 times greater than that of the electron and charge is double than that of a electron. It is accelerated by 5 V of potential difference. Initially the particle was at rest, then its final kinetic energy will be___eV.

Moderate

Solution

Gain in K.E is equal to loss in P.E
$K . E = P . E = q V = (2 e) (5 V) = 10 e V$

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