Q.

A particle has a position vector given by r→=2i^+j^-2k  m and velocity vector v→=i^-j^+k  m/s.  The angular velocity (rad/s) of the particle with respect to the origin at this instant is

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a

i^+4j^+3k9

b

-i^+4j^+3k9

c

-i^-4j^+3k9

d

Zero

answer is B.

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Detailed Solution

ω→=r→×v→r2
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A particle has a position vector given by r→=2i^+j^-2k  m and velocity vector v→=i^-j^+k  m/s.  The angular velocity (rad/s) of the particle with respect to the origin at this instant is