A particle has same range for two angle of projection with same speed 10ms−1 . The corresponding maximum height attained by particle is H1 and H2 , respectively. Then H1+H2 is
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a
10m
b
5m
c
20m
d
cannot be determined
answer is B.
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Detailed Solution
α1+α2=900 H1=u2sin2α12g and H2=u2sin2α22g =u2sin2(900−α1)2g=u2cos2α12g ∴sin2α1+cos2α 1=2gH1u2+2gH2u2 ∴u2=2g(H1+H2) ∴H1+H2=u22g=10×102×10=5m