Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

A particle initially at rest is displaced by applying a non conservative force F in a uniformgravitational field. In the process following physical quantities associated with the particleare measured∆U =change in gravitational potential energy∆K =change in kinetic energy∆W1 =work done by the force F∆W2 = work done by the gravitational force

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya

a

ΔW2=−ΔU

b

ΔK=ΔW1+ΔW2

c

ΔK+ΔU=ΔW1+ΔW2

d

ΔW1=ΔW2

answer is A.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

Use work energy theorem. Also change in potential energy is equql to negative of work done by conservative force and gravitational force is a conservative force .
Watch 3-min video & get full concept clarity
score_test_img

courses

No courses found

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon
A particle initially at rest is displaced by applying a non conservative force F in a uniformgravitational field. In the process following physical quantities associated with the particleare measured∆U =change in gravitational potential energy∆K =change in kinetic energy∆W1 =work done by the force F∆W2 = work done by the gravitational force