A particle initially at rest is displaced by applying a non conservative force F in a uniformgravitational field. In the process following physical quantities associated with the particleare measured∆U =change in gravitational potential energy∆K =change in kinetic energy∆W1 =work done by the force F∆W2 = work done by the gravitational force
see full answer
High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET
🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya
a
ΔW2=−ΔU
b
ΔK=ΔW1+ΔW2
c
ΔK+ΔU=ΔW1+ΔW2
d
ΔW1=ΔW2
answer is A.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
Use work energy theorem. Also change in potential energy is equql to negative of work done by conservative force and gravitational force is a conservative force .
Not sure what to do in the future? Don’t worry! We have a FREE career guidance session just for you!
A particle initially at rest is displaced by applying a non conservative force F in a uniformgravitational field. In the process following physical quantities associated with the particleare measured∆U =change in gravitational potential energy∆K =change in kinetic energy∆W1 =work done by the force F∆W2 = work done by the gravitational force