A particle is making uniform circular motion with angular momentum L. If its kinetic energy is made half and angular frequency be doubled, its new angular momentum m will be
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a
L/4
b
L/2
c
2 L
d
4 L
answer is A.
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Detailed Solution
We know thatL=mvr and E=(1/2)mv2Now L=(2E/v)ror L=2ErÏÃr=2EÏ (âµV=rÏ)When E is halved and Ï is doubled, thenLâ²=2E2Ã2Ï=E2Ï=L4