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Gravitational potential and potential energy

Question

A particle of mass 50 g is kept on the surface of a uniform sphere of mass 120 kg and radius 50 cm. Find the work to be done  in ×1010J against the gravitational force between them to take the particle far away from the sphere. Take G=6.67×1011Nm2kg2.

Moderate
Solution

 Here, M=120kg;m=50g=0.05kg

           R=50cm=0.5m and G=6.67×1011Nm2kg2

Now, initial potential energy of the system of sphere and particle,

Ui=GMmR=6.67×1011×120×0.050.5=8.0×1010J

When the particle is far away from the sphere, the potential energy of the system will be zero i.e. Uf =0
Therefore, required work done, 

                 W=UfUi=08.0×1010=8.0×1010J



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