Questions

# A particle of mass $10g$ moves along a circle of radius $6.4cm$ with a constant tangential acceleration. What is the magnitude of this acceleration if the kinetic energy of the particle becomes equal to  by the end of the second revolution after the beginning of the motion?

## Remember concepts with our Masterclasses.

80k Users
60 mins Expert Faculty Ask Questions
a
0.18 m/s2
b
0.2 m/s2
c
0.1 m/s2
d
0.15 m/s2

Check Your Performance Today with our Free Mock Tests used by Toppers!

detailed solution

Correct option is C

Here, m=10 g=10-2 kgR=6.4 cm=6.4×10-2 m,Kf=8×10-4 J,Ki=0,at=?Using work-energy theorem, Work done by all the forces = Change in KEWtangential force +Wcentripetal force =Kf-Ki⇒  Ft×s+0=Kf-0⇒mat×(2×2πR)=Kf⇒at=Kf4πRm=8×10-44×227×6.4×10-2×10-2=0.099≈0.1 m s-2

+91

Are you a Sri Chaitanya student?

Similar Questions

A particle of mass m is moving in a circular path of constant radius r such that its centripetal  acceleration ac is varying with time to as  ac= k2rt2  where k is a  constant. What is the power  delivered to the particle by the forces acting