A particle of mass $$10g$$ moves along a circle of radius $$6.4cm$$ with a constant tangential acceleration. What is the magnitude of this acceleration if the kinetic energy of the particle becomes equal to $$8$$×$$10-4$$ J by the end of the second revolution after the beginning of the motion?

Question

A particle of mass $$10g$$ moves along a circle of radius $$6.4cm$$ with a constant tangential acceleration. What is the magnitude of this acceleration if the kinetic energy of the particle becomes equal to $$8$$×$$10-4$$ J by the end of the second revolution after the beginning of the motion?

Infinity Learn · Accepted Answer

Here, $$m=10$$ $$g=10-2$$ $$kgR=6.4$$ $$cm=6.4$$×$$10-2$$ m,$$Kf=8$$×$$10-4$$ J,$$Ki=0$$,$$at=$$?Using $$work-energy$$ theorem, Work done by all the forces $$=$$ Change in KEWtangential force $$+Wcentripetal$$ force $$=Kf-Ki$$⇒  Ft×$$s+0=Kf-0$$⇒mat×$$(2$$×$$2$$$$π$$$$R)=Kf$$⇒$$at=Kf4$$$$π$$$$Rm=8$$×$$10-44$$×$$227$$×$$6.4$$×$$10-2$$×$$10-2=0.099$$≈$$0.1$$ m $$s-2$$

A particle of mass $10 g$ moves along a circle of radius $6.4 c m$ with a constant tangential acceleration. What is the magnitude of this acceleration if the kinetic energy of the particle becomes equal to $8 \times 10^{- 4} J$ by the end of the second revolution after the beginning of the motion?

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A particle of mass 10g moves along a circle of radius 6.4cm with a constant tangential acceleration. What is the magnitude of this acceleration if the kinetic energy of the particle becomes equal to 8×10-4 J by the end of the second revolution after the beginning of the motion?

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A particle of mass $10 g$ moves along a circle of radius $6.4 c m$ with a constant tangential acceleration. What is the magnitude of this acceleration if the kinetic energy of the particle becomes equal to $8 \times 10^{- 4} J$ by the end of the second revolution after the beginning of the motion?