Questions
A particle of mass moves along a circle of radius with a constant tangential acceleration. What is the magnitude of this acceleration if the kinetic energy of the particle becomes equal to by the end of the second revolution after the beginning of the motion?
detailed solution
Correct option is C
Here, m=10 g=10-2 kgR=6.4 cm=6.4×10-2 m,Kf=8×10-4 J,Ki=0,at=?Using work-energy theorem, Work done by all the forces = Change in KEWtangential force +Wcentripetal force =Kf-Ki⇒ Ft×s+0=Kf-0⇒mat×(2×2πR)=Kf⇒at=Kf4πRm=8×10-44×227×6.4×10-2×10-2=0.099≈0.1 m s-2Similar Questions
A particle of mass m is moving in a circular path of constant radius r such that its centripetal acceleration ac is varying with time to as ac= k2rt2 where k is a constant. What is the power delivered to the particle by the forces acting
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