A particle of mass $$10g$$ moves along a circle of radius $$6.4$$ cm with a constant tangential acceleration. What is the magnitude of this acceleration, if the kinetic energy of the particle becomes equal to $$8$$×$$10$$−$$4J$$ by the end of the second revolution after the beginning of the motion?

Question

A  particle of mass $$10g$$ moves along a circle of radius $$6.4$$ cm with a constant  tangential acceleration.  What is the  magnitude of this acceleration, if the kinetic energy of the particle becomes  equal to $$8$$×$$10$$−$$4J$$      by the end of the  second revolution after the beginning of the motion?

Infinity Learn · Accepted Answer

$$WTangential=$$Δ$$KE$$$$=Kf$$−Ki $$12MV2=8$$×$$10$$−$$4$$ $$12$$×$$10$$×$$10-2$$×$$V2=8$$×$$10$$−$$4$$ $$V2=16$$×$$10-2---(1)$$ $$V2-U2=2aS$$ $$aT=16$$×$$10$$−$$22(2$$$$π$$r×$$2)=16$$×$$10$$−$$28$$π×$$6.4$$×$$10$$−$$2=0.1ms$$−$$2$$ .

A particle of mass 10g moves along a circle of radius 6.4 cm with a constant tangential acceleration. What is the magnitude of this acceleration, if the kinetic energy of the particle becomes equal to $8 \times 10^{- 4} J$ by the end of the second revolution after the beginning of the motion?

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A particle of mass 10g moves along a circle of radius 6.4 cm with a constant tangential acceleration. What is the magnitude of this acceleration, if the kinetic energy of the particle becomes equal to 8×10−4J by the end of the second revolution after the beginning of the motion?

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A particle of mass 10g moves along a circle of radius 6.4 cm with a constant tangential acceleration. What is the magnitude of this acceleration, if the kinetic energy of the particle becomes equal to $8 \times 10^{- 4} J$ by the end of the second revolution after the beginning of the motion?