A particle of mass 10g is placed in a potential field given by V=(50x2+100)J/Kg. The frequency of oscillation in cycle/sec is

see full answer

Take the SCORE scholarship exam from home and compete for scholarships worth ₹1 crore!*

An Intiative by Sri Chaitanya

10π

5π

100π

50π

answer is B.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

U=(50x2+100)×10−2⇒F=−dUdx=−(100x)10−2⇒mω2x=−(100×10−2)x⇒ω2=100⇒ω=10⇒f=ω2π=5π

Watch 3-min video & get full concept clarity