Questions
A particle of mass 100g is thrown vertically upward with a speed of 5m/s. The work done by the force of gravity during the time the particle goes up is
detailed solution
Correct option is D
Using work energy theorem,work done = change in Kinetic energy → Wtotal=ΔKEi.e. work done by gravity should be equal to change in the kinetic energy of the particle.Wgravity = (KEfinal-KEinitial) Wgravity = (12mv2final-12mv2initial) given mass = 100g ; initial velocity = 5m/s; final velocity = 0; substitute in the above equationWgravity = 0−12×1001000(5)2 =-1.25JWork done by force of gravity = -1.25JTalk to our academic expert!
Similar Questions
If W1, W2 and W3 represent the work done in moving a particle from A to B along three different paths 1, 2 and 3 respectively (as shown) in the gravitational field of a point mass m, find the correct relation between W1, W2 and W3
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