A particle of mass 100g is thrown vertically upward with a speed of 5m/s. The work done by the force of gravity during the time the particle goes up is

Using work energy theorem,work done = change in Kinetic energy → Wtotal=ΔKEi.e. work done by gravity should be equal to change in the kinetic energy of the particle.Wgravity = (KEfinal-KEinitial) Wgravity = (12mv2final-12mv2initial) given mass = 100g ; initial velocity = 5m/s; final velocity = 0; substitute in the above equationWgravity = 0−12×1001000(5)2 =-1.25JWork done by force of gravity = -1.25J